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16x^2-64x+63=0
a = 16; b = -64; c = +63;
Δ = b2-4ac
Δ = -642-4·16·63
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8}{2*16}=\frac{56}{32} =1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8}{2*16}=\frac{72}{32} =2+1/4 $
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